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Two cars moving in opposite directions approach each other with speed of 22m//s and 16.5 m//s respectively.The driver of the first car blows a horn having a frequency 400Hz.The frequency heard by the driver of the second car is[velocity of sound 340 m//s] |
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Answer» Solution :`f_(A) = f [(V+ v_(o))/(v - v_(s))] = 400 [(340 + 16.5)/(340- 22)]` `= 400 [(356.5)/(318)] = 400 xx 1.1210` `f_(A) = 448.4` HZ |
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