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InterviewSolution
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Two cars start off a race with velocity `2 ms^(-1)` and `4ms^(-2)` respectively. What is the length of the path if they reach the final point at the same time ? |
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Answer» Let both particles reach at same position in same time t then from `s=ut+(1)/(2)at^(2)` For 1st particle, `s=4(t)+(1)/(2)(1)t^(2)=4t+(t^(2))/(2)`, For 2nd particle, `s=2(t)+(1)/(2)t^(2)=2t+t^(2)` Equations, we get `4t+(t^(2))/(2)=2t+t^(2)rArr t=4s` Substituting value of t in above equations, we get `s=4(4)+(1)/(2)(1)(4)^(2)=16+8=24m` |
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