Two cells, having the same emf, are connected in series through an external resistance `R`. Cells have internal resistance `r_(1)` and `r_(2) (r_(1) gt r_(2))` respectively. When the circuit is closed, the potentail difference across the first cell is zero the value of `R` isA. `r_(2)-r_(1)`B. `r_(1)-r_(2)`C. `r_(1)+r_(2)`D. `(r_(1)-r_(2))/(2)`

Two cells, having the same emf, are connected in series through an ext

1.	Two cells, having the same emf, are connected in series through an external resistance `R`. Cells have internal resistance `r_(1)` and `r_(2) (r_(1) gt r_(2))` respectively. When the circuit is closed, the potentail difference across the first cell is zero the value of `R` isA. `r_(2)-r_(1)`B. `r_(1)-r_(2)`C. `r_(1)+r_(2)`D. `(r_(1)-r_(2))/(2)`
Answer» Correct Answer - B `i=(E_(1)+E_(2))/(R+r_(1)+r_(2)),V_(1)=E_(1)-ir_(1)`

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