InterviewSolution
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InterviewSolution
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Two cells of emfs 1.5 V and 2.0v having internal resistance 0.2`Sigma` and 0.3 `Sigma` respectively are connected in parallel . Calculate the emf and internal resistance of the equivalent cell . |
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Answer» `E_(1)= 1.5 V " ", " "E_(2) =2V` `r_(1) = 0.2 Sigma " ", " "r_(2) =0.3 Omega` `(1)/(r_(eq) )=(1)/(r_(1))+(1)/(r_(2))=(1)/(0.2)+(1)/(0.3)=(0.5)/(0.06)` ` r_( e q) =(0.06)/(0.5) =(6)/(50)Omega` ` E_( eq) =[(E_(1))/(r_(1)) +(E_(2))/(r_(2))].r_(eq ).=[(1.5)/(0.2) +(2)/(0.3)] xx (6)/(50) =(0.45+0.4)/(0.06)xx(6)/(50)=(0.85)/(0.06) xx (6)/(50) =1.7V` |
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