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Two cells of emfs E1 and E2 and internal resistances r1 and r2 when connected in series and across an external resistance R give a current of 2A. When the polarity of one of the cells is reversed, the current through R is 1A. The ratio E1/E2 = |
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Answer» Two cells of emfs E1 and E2 and internal resistances r1 and r2 when connected in series and across an external resistance R give a current of 2A. When the polarity of one of the cells is reversed, the current through R is 1A. The ratio E1/E2 = |
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