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InterviewSolution
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Two chareged sperical conductors of radill `R_(1) and R_(2)` when connected by a connecting wire acquire charges `q_(1) and q_(2)` respectively. Find the ratio of their charge densities in terms of their radil ? |
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Answer» Two spherical conductors, when connected by a wire will share charges till, they common potential. Thus, `(q_(1))/(4pi in_(0) R_(1)) = (q_(2))/(4pi in_(0) R_(2)) or (q_(1))/(q_(2)) = (R_(1))/(R_(2))` Ratio of surface density of charges is `(sigma_(1))/(sigma_(2)) = (q_(1)//4pi in_(0) R_(1)^(2))/(q_(2)//4pi in_(0) R_(2)^(2)) = (q_(1))/(q_(2)) xx (R_(2)^(2))/(R_(1)^(2)) = (R_(1))/(R_(2)) xx (R_(2)^(2))/(R_(1)^(2)) = (R_(2))/(R_(1))` |
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