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Two charges `+- 10 muC` are placed `5xx10^(-3) m` apart. Determine the electric field at a point `Q, 0*15m` away from O, on a line passing through O and normal to the axis of the diople. |
Answer» Here, `q = +- 10 muC = +- 10xx10^(-6) C`, `2a = 5xx10^(-3) m, r = 0*15m` The point Q lies on equatorial line of electric dipole, `As r gt gt` a So, `E = (p)/(4pi in_(0) r^(3)) = (q(2a))/(4pi in_(0) r^(3))` `E = (9xx10^(9)xx10xx10^(-6)xx5xx10^(-3))/((0*15)^(3))` `= 1*33xx10^(5) NC^(-1)` |
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