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Two circles of radii S em and 3 em intersect at twopoints and the distancebetween their centre is 4 em. Find the length of common chord. |
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Answer» Let the radius of the bigger circle be 'R' and the radius of the smaller circle be 'r'.It is given that R=5cm=OB and r=3cm=OD and AB is the chord whose length we have to find.AD=BD and OD⊥AB(radius is perpendicular to a chord and it divides the chord into two equal parts)therefore, ΔODB is a right angled trianglewhere, OD²+BD²=OB² (3)²+BD²=(5)² 9+BD²=25BD²=25-9BD²=16BD=4cm Since AD=BD=4cm therefore, AB=AD+BD AB=4+4 AB=8cm no it is wrong the length of common cord is 6cm |
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