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Two circles of same radii r and centres O and O' touch each other at P as shown in Fig. If 00' is produced to meet the circle C (O', r) at A and AT is a tangent to the circle C(O, r) such that O'Q ⊥ AT. Then AO: AO' =A. 3/2 B. 2 C. 3 D. 1/4 |
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Answer» Answer is C. 3 Given: AO’ = r O’P = r PO = r AO = AO’ + O’P + PO ⇒ AO = r + r + r ⇒ AO = 3r Now, \(\frac{AO}{AO'}=\frac{3r}{r}\) = 3 Hence, AO: AO’ = 3 |
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