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Two circles of unequal radii have four common tangents. A transverse common tangent meets the direct common tangents at the points P & Q. If length of direct tangent (between the point of contacts) is 8 then length of PQ is |
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Answer» So `PQ=8-a+b` ALSO `QD=QR=8-b` So `QP=8-b+a` `8-a+b=8-b+a` `impliesa=b` `PQ=8`
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