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Two circular discs A and B have equal masses and uniform thickness but have densities `rho_(1)` and `rho_(2)` such that `rho_(1)gt rho_(2)` . Their moments of inertia isA. `I_(1)gt I_(2)`B. `I_(1)gt gt I_(2)`C. `I_(1)ltI_(2)`D. `I_(1)=I_(2)` |
Answer» Correct Answer - C `(I_(1))/(I_(2))=(M_(1))/(M_(2))xx((R_(1))/(R_(2)))^(2)=((R_(1))/(R_(2)))^(2)` `M_(1)=M_(2)` `rho_(1)v_(1)=rho_(2)v_(2)` `rho_(1)pi R_(1)^(2)t=rho_(2)pi R_(2)^(2)t` `(rho_(1))/(rho_(2))=((R_(2))/(R_(1)))^(2)` `therefore (I_(1))/(I_(2))=(rho_(2))/(rho_(1))` As, `rho_(1) gt rho_(1)` `(I_(1))/(I_(2)) lt 1` `I_(1) lt I_(2)`. |
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