Two circular discs are of same thickness. The diameter of `A` is twice that of `B`. The moment of inertia of `A` as compared to that of `B` isA. twice as largeB. four times as largeC. sixteen times as largeD. eight times of large

Two circular discs are of same thickness. The diameter of `A` is twice

1.	Two circular discs are of same thickness. The diameter of `A` is twice that of `B`. The moment of inertia of `A` as compared to that of `B` isA. twice as largeB. four times as largeC. sixteen times as largeD. eight times of large
Answer» Correct Answer - C `(I_(1))/(I_(2))=(M_(1)R_(1)^(2))/(M_(2)R_(2)^(2))` ……(i) `M_(1)=rho v_(1)= rho pi R_(1)^(2)t` `M_(2)= rho v_(2)=rho pi R_(2)^(2) t` `(M_(1))/(M_(2))=(R_(1)^(2))/(R_(2)^(2))` Therefore equation nbo. (i) becomes, `therefore (I_(1))/(I_(2))=((R_(1))/(R_(2)))^(2)xx((R_(1))/(R_(2)))^(2)=((R_(1))/(R_(2)))^(4)` `(I_(1))/(I_(2))=((2R_(2))/(R_(2)))^(4)=16`

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Two circular discs are of same thickness. The diameter of `A` is twice that of `B`. The moment of inertia of `A` as compared to that of `B` isA. twice as largeB. four times as largeC. sixteen times as largeD. eight times of large

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