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Two circular iron discs are of the same thickness. The diameter of A is twice of B . The moment of inertia of A as compared to that of B isA. twice as largeB. four as largeC. 8 time as largeD. 16 times as large |
Answer» Correct Answer - D M.I. of disc `=(1)/(2)mR^(2)=(1)/(2)(pi R^(2)t)rho R^(2)=(1)/(2)pi R^(4)t rho` [`rho` = density, t = thickness] If discs are made of same material and same thickness then `I prop R^(4) prop ("Diameter")^(4)` `therefore (I_(1))/(I_(2))=((D_(A))/(D_(B)))^(4)=((2)/(1))^(4)-(16)/(1)`. |
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