1.

Two closed vessel of equal volume 8.21 L are connected by narrow tube of negligible volume withopen valve. The LHS container is found to contain 3 mole of CO2 & 2 mole of He at 400 K, what ispartial pressure of He in RHS container at 500 K.(8 atm.)

Answer»

P(CO2)=3*0.0821*400/8.21=12atm

P(He)=2*0.0821*400/8.21=8atm

Pressure at 55k

P1/T1=P2/T2

T1=400

T2=500

P1=8atm

8/400=p2/500

P2=4000/400=10atm.=the partial pressure of He in vessel B at 500 K



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