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Two closed vessel of equal volume 8.21 L are connected by narrow tube of negligible volume withopen valve. The LHS container is found to contain 3 mole of CO2 & 2 mole of He at 400 K, what ispartial pressure of He in RHS container at 500 K.(8 atm.) |
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Answer» P(CO2)=3*0.0821*400/8.21=12atm P(He)=2*0.0821*400/8.21=8atm Pressure at 55k P1/T1=P2/T2 T1=400 T2=500 P1=8atm 8/400=p2/500 P2=4000/400=10atm.=the partial pressure of He in vessel B at 500 K |
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