Two coherent monochromatic light beams of intensities I and 4I are superposed. The maximum and minimum possible intensities in the resulting beam areA. 5I and 3IB. 9I and 3IC. 4I and ID. 9I and I

Two coherent monochromatic light beams of intensities I and 4I are sup

1.	Two coherent monochromatic light beams of intensities I and 4I are superposed. The maximum and minimum possible intensities in the resulting beam areA. 5I and 3IB. 9I and 3IC. 4I and ID. 9I and I
Answer» Correct Answer - D We know that That maximum intensity `I_(max)=(sqrt(I_(1))+sqrt(I_(2)))^(2).....(i)` The minimum intensity `I_(min)=(sqrt(I_(1))-sqrt(I_(2)))^(2) ....(ii)` So, the ratio of the maximum and minimum intensities is `I_(max)/I_(min)=(sqrt(I_(1))+sqrt(I_(2)))^(2)/((sqrt(I_(1))-sqrt(I_(2)))^(2))=(sqrt(4I)+sqrt(I))^(2)/((sqrt(4I)-sqrt(I))^(2))` `rArrI_(max)/I_(min)=((3sqrt(I))/(sqrt(I)))^(2)=9/1=9:1` Hence, the maximum and minimum intensities intensible in the resulting pattern are 9I and I

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Two coherent monochromatic light beams of intensities I and 4I are superposed. The maximum and minimum possible intensities in the resulting beam areA. 5I and 3IB. 9I and 3IC. 4I and ID. 9I and I

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