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Two coherent sources of equal intensity produce maximum intensity of `100` units at a point. If the intensity of one of the sources is reduced by 36% reducing its width, then the intensity of light at the same point will beA. (a) 90B. (b) 89C. (c) 67D. (d) 81 |
Answer» Correct Answer - D Intensity of each source `=I_0=(100)/(4)=25unit` If the intensity of one of the source is reduced by 36% then `I_1=25unit` and `I_2=25-25xx(36)/(100)=16(unit)` Hence resultant inensity at the same point will be `I=I_1+I_2+2sqrt(I_1I_2)=25+16+2sqrt(25xx16)=81unit` |
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