1.

Two coils of 10 turns each are arranged such that mutual inductance between them is 150 mH. Magnetic flux linked through one coil when 2 ampere current will flow in another coil:-A. `1xx10^(-3)Wb`B. `10xx10^(-3)Wb`C. `20xx10^(-3)Wb`D. `30xx10^(-3)Wb`

Answer» Correct Answer - D
By `N_(1)varphi_(1)=MI_(2) rArr varphi_(1)=(MI_(2))/(N_(1))`
`=(150xx10^(-3)xx2)/(10)=0.03`


Discussion

No Comment Found

Related InterviewSolutions