Saved Bookmarks
| 1. |
Two coils of self inductance L1 and L2 are connected in series combination having mutual inductance of the coils as M. The equivalent self inductance of the combination will be :(A) 1/L1 + 1/L2 + 1/M(B) L1 + L2 + M(C) L1 + L2 + 2M(D) L1 + L2 - 2M |
|
Answer» Correct option is (D) L1 + L2 - 2M Current on both the inductor is in opposite direction. Hence: Leq = L1 + L2 - 2M |
|