1.

Two coils of self inductance L1 and L2 are connected in series combination having mutual inductance of the coils as M. The equivalent self inductance of the combination will be :(A) 1/L1 + 1/L2 + 1/M(B) L1 + L2 + M(C) L1 + L2 + 2M(D) L1 + L2 - 2M

Answer»

Correct option is (D)  L+ L2 - 2M

Current on both the inductor is in opposite direction.

Hence:

Leq = L1 + L2 - 2M



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