1.

Two coils P and Q are kept near each other. When no current flows through coil P and current increases in coil Q at the rate `10 A//s`, the emf in coil P is 15 mV. When coil Q carries no current and current of `1.8 A` flows through coil P, the magnetic flux linked with the coil Q isA. `1.4 m Wb`B. `2.2 mWb`C. `2.7 m Wb`D. `2.9 m Wb`

Answer» Correct Answer - C
Given, `(dl_(theta))/(dt) = 10A//s`
`e_(p) = 15 mA`
`= 15 xx 10^(-3)V, I_(p) = 18A`
Induced emt in coil P is given as,
`|e_(p)| = M. (dl_(Q))/(dt)`
Substituting the given values, we get
`15 xx 10^(-3) = M xx 10`
`rArr M = 15 xx 10^(-4) H`
Magnetic fluxed linked with coil Q is given as,
`phi_(Q) = MI_(p) = 15 xx 10^(-4) xx 1.8`
`= 27.0 xx 10^(-4)`
`= 2.7 xx 10^(-3) = 2.7 mWb`


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