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Two coins are tossed, find the probabiliti getting 1. both coins heads 2. exactly one head 3. no heads 4. atleast one head. |
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Answer» S = {HH, HT, TH, TT} : n = 22 = 4 1. m = both heads : (HH) =1 P(2H) = m/n = 1/4 2. m = exactly one H: (HT, TH) = 2 P(one heads) = 2/4 = 1/2 3. m : no heads : (TT) =1 P(no head) = p(2T) = 1/4 4. m = atleast one H : (HT, TH, HH) = 3 P(atleast one H) = 3/4. |
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