Two coins are tossed once. Find P(A/B) in each of the following:A = No

1.	Two coins are tossed once. Find P(A/B) in each of the following:A = No tail appears, B = No head appears.
Answer» When two coins are tossed, total outcomes are {HH, HT, TH, TT} = 4 A = No tail occurs = {HH} = 1 Probability f A = P(A) = \(\cfrac14\) B = No head occurs={TT} = 1 Probability of B = P(B) = \(\cfrac14\) (A ∩ B) = No tail and no head occurs = not possible = 0 P (A ∩ B) = \(\cfrac04\) = 0 Hence, \(P(\cfrac{A}{B})=\cfrac{P(A\cap B)}{P(B)}\) \(=\cfrac{0}{1/4} = 0\)

Two coins are tossed once. Find P(A/B) in each of the following:A = No tail appears, B = No head appears.

Answer»

When two coins are tossed, total outcomes are

{HH, HT, TH, TT} = 4

A = No tail occurs = {HH} = 1

Probability f A = P(A) = \(\cfrac14\)

B = No head occurs={TT} = 1

Probability of B = P(B) = \(\cfrac14\)

(A ∩ B) = No tail and no head occurs = not possible = 0

P (A ∩ B) = \(\cfrac04\) = 0

Hence, \(P(\cfrac{A}{B})=\cfrac{P(A\cap B)}{P(B)}\)

\(=\cfrac{0}{1/4} = 0\)

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Two coins are tossed once. Find P(A/B) in each of the following:A = No tail appears, B = No head appears.

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