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Two coins are tossed simultaneous 500 times with the following frequencies of different outcomes. Two tails = 110 times One tail = 200 times No tail = 190 times Find the probability of occurrence of each events. |
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Answer» Let `E_(1)` = getting two tails = 110, `E_(2)` = getting one tail = 200, `E_(3)` = getting no tail = 190. Total number of trials (n) = 500 `P(E_(1))=(E_(1))/(n)=(110)/(500)=(11)/(50)` `P(E_(2))=(E_(2))/(n)=(200)/(500)=(2)/(5)` `P(E_(3))=(E_(3))/(n)=(190)/(500)=(19)/(50)` |
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