Two coins are tossed simultaneously 400 times and we get two heads : 180 times one head : 148 times no head : 72 times . If two coins are tossed at random , what is the probability of getting (i) 2 heads ? (ii) 1 head ? (iii) 0 head ?

Two coins are tossed simultaneously 400 times and we get two heads : 1

1.	Two coins are tossed simultaneously 400 times and we get two heads : 180 times one head : 148 times no head : 72 times . If two coins are tossed at random , what is the probability of getting (i) 2 heads ? (ii) 1 head ? (iii) 0 head ?
Answer» Total number of trials = 400. Number of times 2 heads appear = 180 . Number of times 1 head appears = 148 . Number of times 0 head appears = 72. In a random toss of two coins let `E_(1) , E_(2), E_(3)` be the events of getting 2 heads , 1 head and 0 head respectively . Then , (i) P(getting 2 heads) = `P(E_(1))` = `("number of times 2 heads appear")/("total number of trails")` `= (180)/(400) = (9)/(20) = 0.45` (ii) P (getting 1 head) = `P (E_(2))` `= ("number of times 1 head appears")/("total number of trials")` `= (148)/(400) = (37)/(100) = 0.37`. (iii) P(getting 0 head) = `P (E_(3))` `= ("number of times no head appears")/("total number of trials")` `= (72)/(400) = (18)/(100) = 0.18`.

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Two coins are tossed simultaneously 400 times and we get two heads : 180 times one head : 148 times no head : 72 times . If two coins are tossed at random , what is the probability of getting (i) 2 heads ? (ii) 1 head ? (iii) 0 head ?

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