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Two coins are tossed simultaneously 500 times with the following frequencies of different outcomes: Two heads: 95 timesOne tail: 290 timesNo head : 115 times Find the probability of occurrence of each of these events. |
Answer» We know that, Probability of any event = (Number of favorable outcome) / (Total number of trials) Total number of trials = 95 + 290 + 115 = 500 Now, P(Getting two heads) = \(\frac{95}{500}\) = 0.19 P(Getting one tail) = \(\frac{290}{500}\) = 0.58 P(Getting no head) = \(\frac{115}{500}\) = 0.23 |
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