InterviewSolution
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InterviewSolution
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Two complexes with empirical formula `Co(NH_(3))_(3)(H_(2)O)_(2) Br_(2)CI` exists in two isomeric forms `(A)` and `(B)` Form A gives two moles of AgBr On treatment with `AgNO_(3)` solution whereas form `B` gives only one mole of AgBr Give the structural formula of both these isomers What are these isomer called . |
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Answer» (A) `Co (NH_(3))_(3)(H_(2)O)_(2)Br_(2)CI` gives two moles of AgBr on treatment with `AgNO_(3)` solution hence two `Br^(Θ)` ions are present as counter ion outside the coordination sphere Hence A is `[Co(NH_(3)_(3)(H_(2)O))_(2)CI]Br_(2)` `Co(NH_(3))_(3)(H_(2)O)_(2)CI]Br_(2)rarr[Co(NH_(3))_(3)(H_(2)O)_(2)CI]^(2+) + 2Br^(Θ)` is present as counter ion i .e `B` is `[Co(NH_(3)_(3)(H_(2)O))BrC1]Br.H_(2)O` 1 mole of `H_(2)O` will be present outside the coordination sphere as coordination number of `Co^(3+)` ion is 6 `[Co(NH_(3))_(3)(H_(2)O)BrC]Br.H_(2)O` `rarr[Co(NH_(3))_(3)(H_(2)O)BrCI]^(o+) + Br^(Θ) + H_(2)O` `Br^(Θ) + AgNo_(3)rarrAgBrdarr+ NO_(3)` This isomers are (A) `[Co(NH_(3)_(3)(H_(2)O)_(2)CI]Br_(2)` and (B)`[Co(NH_(3))_(3)(H_(2)O)BrCI]BrH_(2)O` . |
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