InterviewSolution
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InterviewSolution
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Two concentric spheres kept in air have radii R and r. They have similar charge and equal surface charge density `sigma`. The electrical potential at their common centre is (where, `epsi_(0) =` permittivity of free space)A. `(sigma(R+r))/in_(0)`B. `(sigma(R-r))/in_(0)`C. `(sigma(R+r))/(2in_(0))`D. `(sigma(R+r))/(4in_(0))` |
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Answer» Correct Answer - A The potential outside the surface, on the surface and at any point inside the surface is same, `therefore" "V_(1)=1/(4piepsi_(0))q/R` `" "(thereforesigma=q/(4piR^(2))thereforeq=sigma4piR^(2))` `therefore" "V_(1)=1/(4piepsi_(0))(sigma4piR^(2))/R` `V_(1)=(sigmaR)/epsi_(0)` Similarly,`" "V_(2)=(sigmar)/epsi_(0)` Thus, the resultant potential is given by, `V=V_(1)+V_(2)` `=(sigmaR)/epsi_(0)+(sigmar)/epsi_(0)=sigma/epsi_(0)(R+r)` |
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