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Two condensers are in parallel and the energy of the combination is `0.1 J`, when the difference. of potential between terminals is `2 V`. With the same two condensers in series, the energy `1.6 xx 10^-2` J for the same difference of potential across the series combination. What are the capacities? |
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Answer» Correct Answer - A `0.1=1/2(C_1+C_2)(2)^2`………….i `1.6xx10^-2=1/2((C_1C_2)/(C_1+C_2))(2)^2`…………ii Solving these two equations, we can find `C_1` and `C_2` |
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