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Two copper wires have equal length but the thickness of one is twice that of the other. If the resistance of the thin wire is `10 Omega`, find the resistance of the thick wire. |
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Answer» (i) Resistance ` R prop (1)/(A)`. Determine the resistance of the wire using the formula, `(R_(1))/(R_(2))=(A_(2))/(A_(1))` (ii) ` 2.5 Omega` |
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