Two cyclists make the same trip. The first one take 3.5 hours and the second ,with a speed that is 1km/h greater than that of the first ,take 3 hours.find the speed of the two cyclists.also find the distance covered in the trip.

Two cyclists make the same trip. The first one take 3.5 hours and the

1.	Two cyclists make the same trip. The first one take 3.5 hours and the second ,with a speed that is 1km/h greater than that of the first ,take 3 hours.find the speed of the two cyclists.also find the distance covered in the trip.
Answer» N:-Two cyclists make the same TRIP. The first one take 3.5 hours and the second ,with a speed that is 1km/h GREATER than that of the first ,take 3 hours.find the speed of the two cyclists.also find the distance COVERED in the trip.Given:-Two cyclists make the same trip.Time Taken by first cyclist = 3.5 hrsTime Taken by second cyclist = 3 hrsTo Find:-speed of the two cyclists.distance covered in the trip.Solution:-Let the speed of first cyclist be xTime taken by the first cyclist = 3.5 hoursDistance Travelled by first cyclist⇒speed × time⇒ 3.5x We are given that the second with a speed that that is 1 km/h greater than that of the first, TAKES 3 hours .So,The speed of the second cyclist = x + 1Time Taken by second cyclist = 3 hours Distance Travelled by second cyclist ⇒Speed × Time⇒ 3(x + 1)Since we are given that cyclist travelled the same time So,3.5x = 3(x + 1)3.5x = 3x + 30.5 x = 3x = 3/0.5x = 6Distance Travelled by the first cyclist ⇒ 3.5x = 3.5(6)⇒ 21Hence, The distance covered in the trip is 21km━━━━━━━━━━━━━━━━━━━━━━━━━