Two cylindrical rods of uniform cross-section area `A` and `2A`, having free electrons per unit volume `2n` and `n` respectively are joined in series. A current `I` flows through them in steady state. Then the ratio of drift velocity of free electron in left rod to drift velocity of electron in the right rod is `((v_(L))/(v_(R)))` is A. `(1)/(2)`B. 1C. 2D. 4

Two cylindrical rods of uniform cross-section area `A` and `2A`, havin

1.	Two cylindrical rods of uniform cross-section area `A` and `2A`, having free electrons per unit volume `2n` and `n` respectively are joined in series. A current `I` flows through them in steady state. Then the ratio of drift velocity of free electron in left rod to drift velocity of electron in the right rod is `((v_(L))/(v_(R)))` is A. `(1)/(2)`B. 1C. 2D. 4
Answer» Correct Answer - B (b) Since current `I = n e Avd` through both rods is same `2 (n) eAv_(L) = n e (2A) v_(R)` or `(v_(L))/(v_(R)) = 1`

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