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Two diamonds begin a free fall from rest from the same height, 1.0 s apart. How long after the first diamond begins to fall will the two diamonds be 10 m apart? Take `g = 10 m//s^2.` |
Answer» Let the first body for (t) sec and second body for time ( t-10 second when their separation becomes ` 10 m`. Then ` 10 = 1/2 gt^2 - 1/2 g ( t=12) ^2` On solving , ` t= 1.5 s`. |
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