InterviewSolution
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InterviewSolution
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Two dice are rolled simultaneously. Find the probability of (a) getting a total of 11. (b) getting a sum greater that 11 (c) getting a multiple of 2 on one die and a multiple of 3 on the other. |
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Answer» N(S) = 36 Let A : sum is 11 = {(6, 5) (5, 6)) ⇒ n(A) = 2 (a) P(A) = \(\frac{n(A)}{n(S)}\) = \(\frac{2}{36}\) = \(\frac{1}{18}\) (b) Let B = Sum> 11 = {(66)),n(B) = 1 P(B) = \(\frac{n(B)}{n(S)}\) = \(\frac{1}{36}\) (c) Let C = multiple of 2 on one die & multiple of 3 on the other {(2, 3), (2, 6), (4, 3) (4, 6) (6, 3) (6, 6)} n(c) = 6 P(c) = \(\frac{6}{36}\) = \(\frac{1}{6}\) S = {HHH, HHT, HTH, THH TTH, THT, HTT, TTT} |
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