Two dice are rolled simultaneously. The probability that they show dif

1.	Two dice are rolled simultaneously. The probability that they show different faces isA. \(\frac{2}3\)B. \(\frac{1}6\)C.\(\frac{1}3\)D..\(\frac{5}6\)
Answer» Total numbers of elementary events are: 6 x 6 = 36 Let E be the event of getting of showing different faces on both the dice Numbers of favorable events on first dice are: 6 Numbers of favorable events on second dice are: 5 Total numbers of favorable events are = 6 × 5 = 30 P (each dice showing different face) = \(\frac{30}{36}\) = \(\frac{10}{12}\) = \(\frac{5}6\)

Two dice are rolled simultaneously. The probability that they show different faces isA. \(\frac{2}3\)B. \(\frac{1}6\)C.\(\frac{1}3\)D..\(\frac{5}6\)

Answer»

Total numbers of elementary events are: 6 x 6 = 36

Let E be the event of getting of showing different faces on both the dice

Numbers of favorable events on first dice are: 6

Numbers of favorable events on second dice are: 5

Total numbers of favorable events are = 6 × 5 = 30

P (each dice showing different face) = \(\frac{30}{36}\) = \(\frac{10}{12}\) = \(\frac{5}6\)

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Two dice are rolled simultaneously. The probability that they show different faces isA. \(\frac{2}3\)B. \(\frac{1}6\)C.\(\frac{1}3\)D..\(\frac{5}6\)

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