Two dice are thrown at the same time. Find the probability that the su

1.	Two dice are thrown at the same time. Find the probability that the sum of two numbers appearing on the top of the dice is more than 9.
Answer» Given that, Two dice are thrown at same time. Therefore, Total possible outcomes = n(s) = 6 × 6 = 36. Let event E be the event that sum of two numbers appearing on the top is more than 9. Hence, Favorable outcomes of event E = {(4, 6), (5, 5), (5, 6), (6, 5), (6, 6), (6, 4)} Hence, Total outcomes favorable to event E is n(E) = 6. ∴ P(E) = \(\frac{Total\,outcomes\,favourable\,to\,event\,E}{Total\,possible\,outcomes}\) = \(\frac{6}{36}\) = \(\frac{1}{6}\). Hence, Probability of event E is \(\frac{1}{6}\)

Two dice are thrown at the same time. Find the probability that the sum of two numbers appearing on the top of the dice is more than 9.

Answer»

Given that,

Two dice are thrown at same time.

Therefore,

Total possible outcomes = n(s)

= 6 × 6 = 36.

Let event E be the event that sum of two numbers appearing on the top is more than 9.

Hence,

Favorable outcomes of event E = {(4, 6), (5, 5), (5, 6), (6, 5), (6, 6), (6, 4)}

Hence,

Total outcomes favorable to event E is n(E) = 6.

∴ P(E) = \(\frac{Total\,outcomes\,favourable\,to\,event\,E}{Total\,possible\,outcomes}\)

= \(\frac{6}{36}\) = \(\frac{1}{6}\).

Hence,

Probability of event E is \(\frac{1}{6}\)

Discussion

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