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InterviewSolution
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Two dice are thrown simultaneously. Find the probability of getting(i) sum at least ten(ii) a doublet(iii) six as a product |
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Answer» Total number of possible outcomes = 36 (i) Outcomes favourable to given event are: (4, 6), (5, 5), (5, 6), (6, 4), (6, 5), (6, 6) Number of favourable outcomes = 6 P (Sum atleast ten) = 6/36=1/6 (ii) Outcomes favourable to given event are: (1, 1), (2, 2), (3, 3), (4, 4), (5, 5), (6, 6) Number of favourable outcomes = 6 P(a doubtlet) =6/36=1/6 (iii) Outcomes favourable to given event are: (1, 6), (2, 3), (3, 2), (6, 1) Number of favourable outcomes = 4 P (six as a product) =4/36=1/9 |
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