Two dice are thrown simultaneously. The probability of getting the sum

1.	Two dice are thrown simultaneously. The probability of getting the sum divisible by 2, is1. 1/22. 1/33. 1/64. 1/4
Answer» Correct Answer - Option 1 : 1/2 Given: 2 dice thrown simultaneously Calculation: Total number of outcomes n(T) = 6 × 6 = 36 ⇒ Getting the sum divisible by 2 n(E) = {(1,1) (1,3) (1,5) (2,2) (2,4) (2,6) (3,1) (3,3) (3,5) (4,2) (4,4) (4,6) (5,1) (5,3) (5,5) (6,2) (6,4) (6,6)} ⇒ 18 outcomes P(E) = 18/36 = 1/2 ∴ P(E) is 1/2

Two dice are thrown simultaneously. The probability of getting the sum divisible by 2, is1. 1/22. 1/33. 1/64. 1/4

Answer» Correct Answer - Option 1 : 1/2

Given:

2 dice thrown simultaneously

Calculation:

Total number of outcomes n(T) = 6 × 6 = 36

⇒ Getting the sum divisible by 2 n(E) = {(1,1) (1,3) (1,5) (2,2) (2,4) (2,6) (3,1) (3,3) (3,5) (4,2) (4,4) (4,6) (5,1) (5,3) (5,5) (6,2) (6,4) (6,6)}

⇒ 18 outcomes

P(E) = 18/36 = 1/2

∴ P(E) is 1/2

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Two dice are thrown simultaneously. The probability of getting the sum divisible by 2, is1. 1/22. 1/33. 1/64. 1/4

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