Two different dice are rolled together. Find the probability of gettin

1.	Two different dice are rolled together. Find the probability of getting(i)(ii)(iii).the sum of numbers on two dice to be 5,even number on both dicea doublet.
Answer» (i) (1, 4) ; (2, 3) ; (3, 2) and (4, 1) = 4 outcomes Probablity = Number of favorable outcomes/Total number of possible outcome=4/36 = 1/9 (ii) (2, 2) ; (2, 4) ; (2,6) (4, 2) ; (4, 4) ; (4,6) (6, 2) ; (6, 4) and (6, 6) = 9 outcomes Probablity = Number of favorable outcomes/Total number of possible outcome=9/36 = 1/4 iii) (2,2) ; (4,4) ; (3,3) ; (1,1) ; (5,5) ; (6,6) = 6 outcomes Probablity = Number of favorable outcomes/Total number of possible outcome=6/36 = 1/6 Like my answer if you find it useful!

Two different dice are rolled together. Find the probability of getting(i)(ii)(iii).the sum of numbers on two dice to be 5,even number on both dicea doublet.

Answer»

(i) (1, 4) ; (2, 3) ; (3, 2) and (4, 1) = 4 outcomes

Probablity = Number of favorable outcomes/Total number of possible outcome=4/36 = 1/9

(ii) (2, 2) ; (2, 4) ; (2,6) (4, 2) ; (4, 4) ; (4,6) (6, 2) ; (6, 4) and (6, 6) = 9 outcomes

Probablity = Number of favorable outcomes/Total number of possible outcome=9/36 = 1/4

iii) (2,2) ; (4,4) ; (3,3) ; (1,1) ; (5,5) ; (6,6) = 6 outcomes

Probablity = Number of favorable outcomes/Total number of possible outcome=6/36 = 1/6

Like my answer if you find it useful!