Two different dice are thrown together, find the probability that the

1.	Two different dice are thrown together, find the probability that the sum of the numbers appeared is less than 5.
Answer» Total number of outcomes = 6 × 6 = 36 Favourable outcomes = {(1, 1)(1, 2)(1, 3)(2, 1)(2, 2)(3, 1)} Number of favourable outcomes = 6 P(less than 5) = \(\frac{6}{36}\) = \(\frac{1}{6}\)

Two different dice are thrown together, find the probability that the sum of the numbers appeared is less than 5.

Answer»

Total number of outcomes = 6 × 6 = 36

Favourable outcomes = {(1, 1)(1, 2)(1, 3)(2, 1)(2, 2)(3, 1)}

Number of favourable outcomes = 6

P(less than 5) = \(\frac{6}{36}\) = \(\frac{1}{6}\)

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Two different dice are thrown together, find the probability that the sum of the numbers appeared is less than 5.

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