Two different packs of cards are shuffled together. Cards dealt equally among 4 players, each getting 13 cards. The number of ways in which a player get his cards if no two cards are from the same suit with the same denomination isA. `""^(52)C_(13)`B. `2^(13)`C. `""^(52)P_(13)`D. `""^(52)C_(13)xx2^(13)`

Two different packs of cards are shuffled together. Cards dealt equall

1.	Two different packs of cards are shuffled together. Cards dealt equally among 4 players, each getting 13 cards. The number of ways in which a player get his cards if no two cards are from the same suit with the same denomination isA. `""^(52)C_(13)`B. `2^(13)`C. `""^(52)P_(13)`D. `""^(52)C_(13)xx2^(13)`
Answer» Here, we have 52 cards, each card being 2 in number. It is given that no two are to be of the same suit with the same denomination. So, we first draw 13 cards from 52 cards. This can be done in `""^(52)C_(13)` ways. Now each of 13 cards selected can be chosen in 2 ways either from first pack or from 2nd pack. Hence, required number of ways `=""^(52)C_(13)xx2^(13)`.

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