Two electrochemical cell Zn|Zn^(2+)||Cu^(2+)|CuFe |Fe^(2+)|Cu^(2+)|Cu are connected in series what will be the net e.m.f of the cell at 25^(@)C ? Give : Zn^(2+)|Zn=-0.76 V Cu^(2+)|Cu=+0.34 v,Fe^(2+)|Fe=-0.41V

Two electrochemical cell Zn|Zn^(2+)||Cu^(2+)|CuFe |Fe^(2+)|Cu^(2+)|Cu

1.	Two electrochemical cell Zn\|Zn^(2+)\|\|Cu^(2+)\|CuFe \|Fe^(2+)\|Cu^(2+)\|Cu are connected in series what will be the net e.m.f of the cell at 25^(@)C ? Give : Zn^(2+)\|Zn=-0.76 V Cu^(2+)\|Cu=+0.34 v,Fe^(2+)\|Fe=-0.41V
Answer» `+1.85 V` `-1.85 V` `+0.83 V` `-0.83 V` Solution :EMF for the CELL `Zn\|Zn^(2+)\|CU^(2+)\|Cu=0.34-(-0.76)=0.75V` SINCE the two CELLS are connected in series therefore the NET EMF of the two cells =1.10 +0.75 =1.85 V