1.

Two electrolytic cell are attached in series and current is passing through them. First electrolytic cell X(NO_(3))_(3(aq)) and second electrolytic cell posses Y(NO_(3))_(2) and molecular mass of X and Y are 1:2 respectively. Hence what is the ratio of lierated mass ?

Answer»

`3:2`
`1:2`
`1:3`
`3:1`

Solution :OXIDATION STATE of X and Y are `X^(3+) and Y^(2+)` respectively,
Molecular MASS ratio=1:2 and so EQUIVALENT mass`=(1)/(3):(2)/(2) or 1:3`.


Discussion

No Comment Found

Related InterviewSolutions