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Two electrolytic cells containing silver nitrate solution and copper sulphate solution are connected in series. A steady current of 2.5 amp was passed through them till 1.078 g of Ag were deposited. How long did the current flow ? What weight of copper will be deposited ? (Ag = 107.8 u, Cu = 63.5 u) |
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Answer» Solution :`w=zxxixxt` `t=(w)/(zxxi)` `t=(1.078xx1xx96500)/(107.8xx2.5)="386 SECONDS"` `Cu^(2+)+2E^(-)rarrCu` `w=(63.5)/(2xx96500)xx2.5xx386="0.3175 gram"` |
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