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Two equal circles of radius r intersect such that each passes through the center of the other. The lenght of the common chord isA. sq root of rB. r × sq root of 2C. r × sq root of 3D. (r × sq root of 3) ÷ 2

Answer» Two equal circles of radius r intersect such that each passes through the center of the other. The lenght of the common chord is
A. sq root of r
B. r × sq root of 2
C. r × sq root of 3
D. (r × sq root of 3) ÷ 2


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