InterviewSolution
Saved Bookmarks
| 1. |
Two equal circles of radius r intersect such that each passes through the center of the other. The lenght of the common chord isA. sq root of rB. r × sq root of 2C. r × sq root of 3D. (r × sq root of 3) ÷ 2 |
|
Answer» Two equal circles of radius r intersect such that each passes through the center of the other. The lenght of the common chord is A. sq root of r B. r × sq root of 2 C. r × sq root of 3 D. (r × sq root of 3) ÷ 2 |
|