Two equal drops of water are falling through air with a steady velocity v. If the drops coalesced, what will be the new velocity?

Two equal drops of water are falling through air with a steady velocit

1.	Two equal drops of water are falling through air with a steady velocity v. If the drops coalesced, what will be the new velocity?
Answer» `(4)/(3)piR^(3)xxrho=(4)/(3)pir^(3)xxrho+(4)/(3)pir^(3)xxrho` or `R=(2^((1)/(3)))r` and `v_(t)alphar^(2)` (stokes now) `(v^(1))/(v)=(R^(2))/(r^(2))=2^(2//3)` `:. v^(1)=2^(2//3)`

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Two equal drops of water are falling through air with a steady velocity v. If the drops coalesced, what will be the new velocity?

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