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Two equal forces have their resultant equal to either. What is the inclination between them? |
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Answer» \(Given,|\vec A +\vec A |= |\vec A|\) ⇒ \(\sqrt {A^2 +A^2 +2A.A.cos \theta}\) = A ⇒ 2A2 (1 + cosθ) = A2 ⇒ 1 + cosθ = \(\frac{1}{2}\) ⇒ cosθ = \(\frac{-1}{2}\) ⇒ θ = 120° |
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