Two equal spheres A and B lie on a smooth horizontal circular groove at opposite ends of a diameter. At time t = 0, A is projected along the groove and it first impinges on B at time t = T_(1) and again at time t = T_(2). If e is the coefficient of restitution, the ratio T_(2)//T_(1) is

Two equal spheres A and B lie on a smooth horizontal circular groove a

1.	Two equal spheres A and B lie on a smooth horizontal circular groove at opposite ends of a diameter. At time t = 0, A is projected along the groove and it first impinges on B at time t = T_(1) and again at time t = T_(2). If e is the coefficient of restitution, the ratio T_(2)//T_(1) is
Answer» `2/e` `((2+e))/2` `(2(e+1))/e` `((2+e))/e` Solution :`T_(1)=(piR)/u_(1)` `(v_(2)-v_(1))/u_(1)=eimpliesv_(2)-v_(1)-eu_1` TIME TAKEN to collide `A` and `B` again is `T_(2)-T_(1)=(2piR)/(v_(2)-v_(1)) implies T_(2)-T_(1)=(2piR)/(eu_(1))`………..ii Dividing ii by i, we get `T_(2)/T_(1)=(2+e)/e`