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Two exactly similar wire of steel and copper are stretched by equal force. If the difference in their elongations is 0.5 cm, the elongation `(l)` of each wire is `Y_(s)("steel") =2.0xx10^(11) N//m^(2)` `Y_(c)("copper")=1.2xx10^(11)N//m^(2)`A. `l_(s)=0.75 cm,l_(c)=1.25 cm`B. `l_(s)=1.25 cm,l_(c)=0.75 cm`C. `l_(s)=0.25 cm,l_(c)=0.75 cm`D. `l_(s)=0.75cm,l_(c)=0.25 cm` |
Answer» Correct Answer - A |
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