1.

Two faradays of electricity are passed through a solution of CuSO_(4). The mass of copper deposited at the cathode (at. Mass of Cu=63.5 amu)

Answer»

2 g
127 g
0 g
63.7 g

Solution :`CU^(2+)+2e^(-)toCu`
Thus, 2F charge deposit 1 MOL of Cu, i.e., 63.5g.


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