1.

Two faradays of electricity are passed through a solution of CuSO_(4).The mass of copper deposited at the cathode is (atomic mass of Cu=63.5 g)

Answer»

2 G
127 g
0 g
63.5 g

Solution :(d) The REDUCTION REACTION is :
`Cu^(2+)(aq)+underset(2F)2e^-) to underset(=63.5 g)underset(1 g" atom")(Cu(s))`


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