1.

Two first order reactions half lives in the ratio 3:2. If t_(1) and t_(2) are the time periods for 25% and 75% completion for the first and second reactions respectively, find t_(1):t_(2)

Answer»

`0.0311:1`
`0.420:1`
`0.273:1`
`0.119:1`

SOLUTION :`((0.693/(3X)xxt_(1)))/((0.693/(2x)xxt_(2)))=(log(100/75))/(log(100/25)),(2x)/(3x)XX(t_(1))/(t_(2))=(log(4/3))/(2log2),(t_(1))/(t_(2))=3/2xx0.1249/(2xx0.3010)=0.311`


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